
Finding a basis of an infinite-dimensional vector space?
For many infinite-dimensional vector spaces of interest we don't care about describing a basis anyway; they often come with a topology and we can therefore get a lot out of studying dense …
general topology - Why is the infinite sphere contractible ...
Why is the infinite sphere contractible? I know a proof from Hatcher p. 88, but I don't understand how this is possible. I really understand the statement and the proof, but in my imagination this...
One divided by Infinity? - Mathematics Stack Exchange
Infinite decimals are introduced very loosely in secondary education and the subtleties are not always fully grasped until arriving at university. By the way, there is a group of very strict …
infinity - What is the definition of an infinite sequence ...
May 12, 2024 · Except for $0$ every element in this sequence has both a next and previous element. However, we have an infinite amount of elements between $0$ and $\omega$, which …
How can I define $e^x$ as the value of infinite series?
Are you familiar with Taylor series? Series solutions of differential equations at regular points? From what foundation/background are you approaching this problem?
elementary set theory - What do finite, infinite, countable, not ...
What do finite, infinite, countable, not countable, countably infinite mean? [duplicate] Ask Question Asked 13 years, 2 months ago Modified 13 years, 2 months ago
What is the difference between "infinite" and "transfinite"?
Jun 6, 2020 · The reason being, especially in the non-standard analysis case, that "infinite number" is sort of awkward and can make people think about ∞ ∞ or infinite cardinals …
If $S$ is an infinite $\sigma$ algebra on $X$ then $S$ is not …
6 Show that if a $\sigma$-algebra is infinite, that it contains a countably infinite collection of disjoint subsets. An immediate consequence is that the $\sigma$-algebra is uncountable.
elementary set theory - What is the definition for an infinite set ...
Dec 3, 2020 · However, while Dedekind-infinite implies your notion even without the Axiom of Choice, your definition does not imply Dedekind-infinite if we do not have the Axiom of Choice …
Infinite intersection of open sets - Mathematics Stack Exchange
Oct 2, 2015 · Similarly, to disprove infinite intersection of open sets is open, it is enough to give a particular collection of open sets such that intersection is not open.